d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1<\/strong> b\u1ea1ch th\u1ee7 hay k\u1ebft h\u1ee3p t\u1ea1o 3 c\u00e0ng. Ph\u1ee5 thu\u1ed9c v\u00e0o nh\u1eefng c\u00e1ch \u00e1p d\u1ee5ng s\u1ed1 b\u00f3ng s\u1ebd ra \u0111\u01b0\u1ee3c nh\u1eefng l\u1ef1a ch\u1ecdn kh\u00e1c nhau. Tuy nhi\u00ean c\u00e1ch quy \u0111\u1ed5i \u0111\u1ec1u nh\u01b0 sau:<\/p>\n1 c\u00f3 s\u1ed1 b\u00f3ng t\u01b0\u01a1ng \u0111\u01b0\u01a1ng 6<\/p>\n
2 c\u00f3 s\u1ed1 b\u00f3ng t\u01b0\u01a1ng \u0111\u01b0\u01a1ng 7<\/p>\n
3 c\u00f3 s\u1ed1 b\u00f3ng t\u01b0\u01a1ng \u0111\u01b0\u01a1ng 8<\/p>\n
4 c\u00f3 s\u1ed1 b\u00f3ng t\u01b0\u01a1ng \u0111\u01b0\u01a1ng 9<\/p>\n
5 c\u00f3 s\u1ed1 b\u00f3ng t\u01b0\u01a1ng \u0111\u01b0\u01a1ng 0<\/p>\n
T\u00ednh v\u00f2ng l\u1eb7p \u00e2m d\u01b0\u01a1ng ng\u0169 h\u00e0nh<\/h3>\n
V\u00f2ng \u00e2m d\u01b0\u01a1ng c\u0169ng \u0111\u01b0\u1ee3c bi\u1ebft t\u1edbi trong d\u1ef1 \u0111o\u00e1n k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc. C\u00e1ch quy \u0111\u1ed5i c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
Kim = 2. M\u1ed9c = 5. H\u1ecfa = 3. Th\u1ee7y =1. Th\u1ed5 = 4.<\/p>\n
Kim = 7. M\u1ed9c = 0. H\u1ecfa = 8. Th\u1ee7y = 6. Th\u1ed5 = 9. (Chi\u1ebfu theo b\u00f3ng \u1edf tr\u00ean c\u00f3 c\u00e1ch quy \u0111\u1ed5i kh\u00e1c)<\/p>\n
Kim -> M\u1ed9c -> H\u1ecfa -> Th\u1ee7y -> Th\u1ed5 -> Kim. (Ng\u0169 h\u00e0nh t\u01b0\u01a1ng sinh trong phong th\u1ee7y)<\/p>\n
t\u1ee9c : 2->5->3->1->4->2 v\u00e0 7->0->6->9->7 (Quy \u0111\u1ed5i theo con s\u1ed1)<\/p>\n
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