L\u00f4 tr\u01b0\u1ee3t l\u00e0 g\u00ec?<\/h2>\n
L\u00f4 tr\u01b0\u1ee3t<\/strong> l\u00e0 nh\u1eefng con l\u00f4 kh\u00f4ng v\u1ec1 (tr\u01b0\u1ee3t \u2013 h\u1ee5t \u2013 kh\u00f4ng n\u1ed5) tr\u00ean b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1. L\u00f4 \u0111\u1ec1 c\u00f3 100 s\u1ed1 t\u1eeb 00 \u2013 99, m\u1ed7i ng\u00e0y s\u1ebd c\u00f3 \u00edt nh\u1ea5t 73 con l\u00f4 tr\u01b0\u1ee3t sau khi tr\u1eeb \u0111i 23 con l\u00f4 \u0111\u1ec1 \u0111\u00e3 n\u1ed5 n\u00ean t\u1ef7 l\u1ec7 chi\u1ebfn th\u1eafng s\u1ebd cao h\u01a1n h\u1eb3n so v\u1edbi ch\u01a1i l\u00f4 b\u00ecnh th\u01b0\u1eddng.<\/p>\n Ch\u00ednh v\u00ec t\u1ef7 l\u1ec7 chi\u1ebfn th\u1eafng cao n\u00ean nh\u00e0 c\u00e1i bu\u1ed9c nh\u1eefng ng\u01b0\u1eddi ch\u01a1i l\u00f4 tr\u01b0\u1ee3t<\/strong> ph\u1ea3i ch\u1ecdn xi\u00ean 4, xi\u00ean 8, xi\u00ean 10 \u0111\u1ec3 \u0111\u00e1nh t\u01b0\u01a1ng \u1ee9ng v\u1edbi tr\u01b0\u1ee3t 4, 8 ho\u1eb7c 10 s\u1ed1 c\u00f9ng l\u00fac th\u00ec m\u1edbi chi\u1ebfn th\u1eafng v\u00e0 nh\u1eadn \u0111\u01b0\u1ee3c ph\u1ea7n th\u01b0\u1edfng t\u01b0\u01a1ng \u1ee9ng t\u0103ng d\u1ea7n, c\u1ee5 th\u1ec3:<\/p>\n Th\u1ebf n\u00ean anh em c\u1ea7n t\u00ednh to\u00e1n \u0111i\u1ec3m l\u00f4, v\u1ed1n, c\u00e1ch v\u00e0o ti\u1ec1n th\u1ebf n\u00e0o cho ph\u00f9 h\u1ee3p \u0111\u1ec3 an to\u00e0n nh\u1ea5t th\u00ec s\u1ebd t\u1ed1i \u01b0u kh\u1ea3 n\u0103ng chi\u1ebfn th\u1eafng h\u01a1n r\u1ea5t nhi\u1ec1u.<\/p>\n T\u1ef7 l\u1ec7 b\u1eaft d\u00ednh l\u00f4 tr\u01b0\u1ee3t<\/strong> s\u1ebd cao h\u01a1n ch\u01a1i l\u00f4 b\u00ecnh th\u01b0\u1eddng, tuy nhi\u00ean l\u00e0 b\u1ea1c th\u1ee7 chuy\u00ean nghi\u1ec7p th\u00ec anh em tuy\u1ec7t \u0111\u1ed1i kh\u00f4ng b\u1eaft b\u1eeba v\u00f4 c\u0103n c\u1ee9 m\u00e0 h\u00e3y \u00e1p d\u1ee5ng soi c\u1ea7u, ph\u00e1n \u0111o\u00e1n t\u1eeb \u0111\u00f3 t\u00ecm ra l\u00f4 xi\u00ean tr\u01b0\u1ee3t<\/strong> \u0111\u1eb9p \u0111\u1ec3 \u0111\u00e1nh. Lu\u00f4n h\u1ecdc h\u1ecfi, trau d\u1ed3i kinh nghi\u1ec7m c\u00e1ch b\u1eaft l\u00f4<\/strong> \u0111\u1ec3 kh\u1ea3 n\u0103ng c\u1ea3m s\u1ed1 ng\u00e0y m\u1ed9t gia t\u0103ng.<\/p>\n\n
5 C\u00e1ch b\u1eaft l\u00f4 tr\u01b0\u1ee3t \u0111\u1ec9nh cao<\/h2>\n
1. B\u1eaft l\u00f4 tr\u01b0\u1ee3t d\u1ef1a tr\u00ean th\u1ed1ng k\u00ea l\u00f4 khan<\/h3>\n