.<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\nX\u00e9t trong KQXSMB ng\u00e0y 16\/1\/2024 ta c\u00f3:<\/p>\n
\u2b50 L\u00f4 2 nh\u00e1y 09 => H\u00f4m nay s\u1ebd c\u00f3 98<\/p>\n
\u2b50 H\u00f4m tr\u01b0\u1edbc c\u00f3 c\u1eb7p s\u1ed1 34 => Nhi\u1ec1u kh\u1ea3 n\u0103ng h\u00f4m nay s\u1ebd c\u00f3 89<\/p>\n
\u2b50 Ngo\u00e0i ra h\u00f4m tr\u01b0\u1edbc v\u1ec1\u00a0 l\u00f4 k\u00e9p 00 => L\u00f4 h\u00f4m nay s\u1ebd v\u1ec1 88<\/p>\n
\u2b50 \u0110\u1ea7u l\u00f4 t\u00f4 mi\u1ec1n b\u1eafc h\u00f4m tr\u01b0\u1edbc c\u00e2m: 9<\/p>\n
\u2b50 \u0110\u00edt (\u0110u\u00f4i) l\u00f4 t\u00f4 h\u00f4m tr\u01b0\u1edbc c\u00e2m: 6<\/p>\n
\u2b50\u00a0Th\u1ed1ng k\u00ea t\u1ea7n su\u1ea5t l\u00f4\u00a0v\u1ec1 nhi\u1ec1u nh\u1ea5t:\u00a094<\/strong><\/p>\n\u2b50 D\u00e0n l\u00f4 \u0111\u1ec1 t\u1ed5ng hi\u1ec7u qu\u1ea3 h\u00f4m nay t\u1ed5ng: 4<\/p>\n
\u2b50\u00a0Ch\u1ea1m \u0111\u1ec1\u00a0l\u00e2u ch\u01b0a xu\u1ea5t hi\u1ec7n nh\u1ea5t:\u00a05<\/strong><\/p>\nCH\u1ed0T S\u1ed0 \u0110\u1eb8P D\u1ef0 \u0110O\u00c1N L\u00d4 T\u00d4 B\u1ea0CH TH\u1ee6 MI\u1ec0N B\u1eaeC<\/strong><\/h3>\n? \u0110\u1ea7u \u0111u\u00f4i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t: 85<\/p>\n
? C\u1eb7p l\u00f4 t\u00f4 2 s\u1ed1 \u0111\u1eb9p h\u00f4m nay: 45-36<\/p>\n
? Loto xi\u00ean 2, 3: 25-30-12<\/p>\n
? L\u00f4 k\u00e9p: 22<\/p>\n
? Soi c\u1ea7u VIP 4 s\u1ed1:\u00a0.25-36-25-04<\/strong><\/p>\n\u0110\u1ea7u \u0111u\u00f4i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t:\u00a0 28<\/p>\n
L\u00f4 t\u00f4 2 s\u1ed1 ch\u1eafc v\u1ec1: 25<\/p>\n
Loto xi\u00ean 2, 3: 57-98-30<\/p>\n
L\u00f4 k\u00e9p: 88<\/p>\n
TH\u1ed0NG K\u00ca L\u00d4 T\u00d4 MI\u1ec0N B\u1eaeC NG\u00c0Y 16\/1\/2024<\/b><\/h2>\n
<\/p>\n
Th\u1ed1ng k\u00ea mi\u1ec1n B\u1eafc c\u1eb7p l\u00f4 \u0111\u1eb9p h\u00f4m nay v\u1ec1 nhi\u1ec1u: 01<\/p>\n
L\u00f4 t\u00f4 gan l\u00e2u ra nh\u1ea5t: 36<\/p>\n
Ch\u1ea1m \u0111\u1ea7u \u0111u\u00f4i \u0111\u1eb7c bi\u1ec7t l\u00e2u ch\u01b0a xu\u1ea5t hi\u1ec7n: 29<\/p>\n
\u0110\u1ea7u c\u00e2m kh\u00f4ng c\u00f3, \u0111\u00edt (\u0111u\u00f4i) l\u00f4 c\u00e2m kh\u00f4ng c\u00f37<\/p>\n
2 s\u1ed1 cu\u1ed1i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t mi\u1ec1n B\u1eafc theo tu\u1ea7n: 58<\/p>\n